Conceptual Questions (5 points each)
Questions 1 -- 6 refer to the following situation:
Mystery substance X has the following thermodynamic data:
(c) 100 kcal
To heat liquid X through
C requires
(d) 150 kcal
To boil liquid X at 210
C requires
Note that
, the heat of vaporization, applies
to boiling the liquid; not
, the heat of fusion, which applies to
the melting/freezing transition.
(d) Liquid X's volume decreases by 4%.
The fractional change in volume, for
C, is
for a decrease of 4%.
(c) 0.6 W
The sample loses radiative energy because it emits more energy than it absorbs. Specifically, it loses energy at the rate
where
all temperatures are expressed in Kelvin. When the room temperature is
increased to
C, this rate changes because
is altered by a factor
Since the old rate of energy loss,
, is given as 1 W,
the rate in the warmer room must be 0.6 W.
Questions 5 and 6 pertain to the following specific process undergone by substance X:
1 kg of substance X is heated from an initial temperature of -10
C to a final state which is a mixture of 0.3 kg of liquid X and 0.70 kg of gas X.
Questions 7 through 12 pertain to the situation described below:
An ideal monatomic gas originally in state A at temperature 27
C can
be taken to state B at temperature
via any of the thermodynamic
processes shown.
For these questions you may choose to use the ideal gas constants
,
though they are not strictly necessary.
(a)
Work done by the gas is given by the area under the PV curve. By inspection (for example, counting up full boxes under the curves), this is greatest for I, then smaller for II, then III, then IV.
(b) 600 J
Process I occurs at constant pressure, so the work done by the gas is just
which, given the conversion factor, is 600 J.
(d) 327
C
This can be found from the ideal gas law, for constant n, where all temperatures must be expressed in Kelvin:
(b) 1.6 J/K
Since the ideal gas expands isothermally,
and Q= W = 480 J.
is just defined as Q/T, where T is the temperature of the constant temperature process, expressed in Kelvin. This is given as
, so
Questions 11 and 12 both refer to process IV, where the gas expands
from state A to state D adiabatically, with
C.
(a) -225 J
The change in internal energy, for this ideal monatomic gas, is
Here
K. But 150 K is
, so using the ideal gas law we find
which gives -225 J using the 1 atm l = 100 J conversion factor.
(b) 225 J
Since process AD is adiabatic,
,
telling us the gas does W = 225 J of work from A to D, using our
answer to 11. Since process DB is isochoric (constant volume), the gas
does no further work from D to B. Thus the gas does a total of 225 J
of work in process IV.
Questions 13 and 14 pertain to the following situation:
A heat engine operates between a hot reservoir at 1500 K and a cold
reservoir at 500 K.
J of heat is removed from the
hot reservoir and
J of work is performed.
(a) 0.15
The engine has efficiency
(d) 0.67
The Carnot efficiency of the engine is
Quantitative Problems (Point Value as Marked)
while the heat of fusion for water is
.
First, were the water to cool to
C, it would give up
This is not enough to heat the copper to the same temperature,
C,
so the water must continue to give up heat.
Next, were the water to fully freeze at
C, it would give up an additional
Together with the heat lost by the water in
cooling, this is more than enough to heat the copper to the same final
temperature,
C. Thus we know that the final temperature must be
C, with only a portion of the water frozen to ice so that, in reaching the final state,
.
Setting up this equality,
using our partial results above. Thus
and
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