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Homework #10
Conceptual Solution

  1. (b) For the Bohr atom, the energy levels are

    displaymath50

    Here the ground state energy level, with n=1, has tex2html_wrap_inline54 , so that tex2html_wrap_inline56 and Z=2, corresponding to He. Since it is a one electron ion, the He must be singly ionized, tex2html_wrap_inline60 .

  2. (d) Again, the energy levels are tex2html_wrap_inline62 , so

    displaymath64

  3. (a) The ionization energy is the energy required to remove the electron from its usual, ground state (n=1) from the potential well of the atom, giving it final energy zero so that it is not trapped inside the atom. This is just minus tex2html_wrap_inline68 , or 54.4 eV.
  4. (c) Since for a photon tex2html_wrap_inline70 , the photon with the longest wavelength has the smallest energy. This occurs for the transition with the smallest energy change between initial and final electron energy levels (since the photon carries the difference in those 2 energies). That transition is C, between levels 3 and 4.
  5. (b) Transition E goes from electron atomic energy level 2 to 3, requiring absorption of a photon with energy

    displaymath72

  6. (e) Transition A goes from electron atomic energy level 2 to 1, emitting a photon with energy

    displaymath74

    To obtain the momentum of the photon, we recall that

    displaymath76

    for the photon, since its tex2html_wrap_inline78 obeys tex2html_wrap_inline80 (which is not true for massive particles). Converting tex2html_wrap_inline78 into SI units and dividing by c gives

    displaymath86

  7. (b) A photon is emitted when the electron gives off energy in the transition, by dropping to a lower energy level; a photon is absorbed in providing the energy for an electron to raise its energy level to a higher level. In transitions A and B, the electron gives off energy by emitting a photon; while in C, D, and E, it gains energy by absorbing a photon.





Katherine Benson
Fri Apr 23 10:40:06 PDT 1999