with r and
as given in section 1.9:
The full solution will also have the
general, underdamped homogeneous oscillator solution added to
,
with coefficients fixed by the initial conditions. (This general
homogeneous solution is also called the transient solution, because it
decays exponentially in time.) Here, however, we're asked to find
initial conditions such that steady state motion begins instantly;
that is, we don't have to wait for the transient to decay, because its
coefficients are zero. In that case the full solution is
, with
velocity
This obeys initial conditions
using the oddness of sin. Note that our derivation of the response factor in section 1.9 (especially equations 1.120 - 1.123), lets us write out
and
explicitly, since
giving
Thus our initial conditions are
In section 1.9 we derived the solution when the right hand side
of the equation (the source) was
:
Note, for complex solutions z = w + ix, that the imaginary part of equation
(2) is exactly equation (1), since
. Thus, knowing our solution z to equation
(2) gives us the solution x for a sinusoidal source, since
.
Recall that equation (2) gave the particular solution
where
Thus
for a critically damped oscillator with
. Our ODE is thus
We seek a particular solution proportional to the source,
. Noting that
, plugging into our ODE gives
Thus we have particular solution
and are encouraged to try
. This guess has derivatives
Plugging into our ODE gives
or, noting that
and
terms cancel,
This works if it's a time-independent equation, that is, if n=2, in which case it gives solution 2A = f. Thus we have particular solution
with initial conditions
. Note that
so that, by superposition, it gives a particular solution which is half the sum of particular solutions in (a) and (b):
Our most general solution is given by this particular solution plus the general solution
to the homogeneous problem (a critically damped oscillator with
). This is
Thus we have solution
with derivative
At t= 0 this gives
Imposing our initial conditions
gives
. Thus our solution obeying these initial conditions is
as the net voltage
drop along the full circuit loop must be zero. This is an ODE with constant coefficients, whose solution
must obey
Thus the general solution is the exponentially decaying
(There is only one independent solution as this is a first order ODE.)
(Traversing the circuit
clockwise from the switch, we have a voltage gain
followed
by voltage drops
and q/C, with the total gain
balancing the total drop.) Looking for a constant particular solution
, the ODE requires
Applying the initial condition q(0) = 0 gives
. Thus we have solution
with current
(Traversing the circuit clockwise from the switch, we have a voltage
gain
followed by voltage drops
and q/C, with the total gain balancing the total drop.)
We seek a particular solution to the inhomogeneous ODE
We try a solution proportional to the source,
Plugging into the ODE gives
solved by
defining
.
Taking our independent homogeneous solutions as
we obtain
with derivative
Setting our initial conditions
gives
giving solution
Taking
,
Thus
As
, all terms with positive powers of
vanish, leaving only the
term: