For the central force potential V(r), we thus have
The conjugate momenta are
Thus
is the conserved energy.
Hamilton's equations give
The equations on the right just reproduce the relations between
and
,
and
. Using them to eliminate momenta and substitute into the Hamilton's equations on the left gives
reproducing the Euler-Lagrange equations in Equation 3.40.
Here
is constant and
so we have
For the gravitational potential mgz, we thus have
This Lagrangian has partial derivatives
giving Euler-Lagrange equation
or
so
is the conserved energy.
The equation on the right just reproduces the relations between
and
. Eliminating
in Hamilton's equation on the left gives
reproducing the Euler-Lagrange equation in part (a).
Only the component of gravity parallel
to the wire gives an unopposed force accelerating the bead; that
component is
. Then only the vertical component of the
unopposed force accelerates the z-component; this is
. Thus wise application of Newton II leads to
in agreement with the equation of motion from parts (a) and (c).
which has asymptotes
decreasing from infinity for small
r, and cr diverging to infinity as
. In between the decreasing behavior at small r
and the increasing behavior at large r must be a turnover point
where
has a minimum. The potential thus looks as sketched
above, with bound orbits for all allowed energies.
giving a minimum at
It has period
which is positive, indicating a stable orbit. Thus
Since these frequencies are not rational multiples, the near-circular orbits never close (become periodic).
which has asymptotes
decreasing from infinity for small
r, and
diverging to infinity as
. In between the decreasing behavior at small r
and the increasing behavior at large r must be a turnover point
where
has a minimum. The potential thus looks as sketched
above, with bound orbits for all allowed energies.
giving a minimum at
It has period
Evaluating this at
gives
so that