next up previous
Next: About this document

We continued the discussion of 2-body central force motion, whose Lagrangian we had previously shown to decouple when written in terms of the center of mass coordinate tex2html_wrap_inline43 and relative coordinate tex2html_wrap_inline45 . Moreover, tex2html_wrap_inline47 is just the Lagrangian for a free particle: the E-L equations for tex2html_wrap_inline49 just tell us that tex2html_wrap_inline51 must remain constant -- the center of mass continues along at constant velocity, insensitive to the interactions between the two particles.

The interesting dynamics is therefore all in the relative motion tex2html_wrap_inline53 , governed by the Lagrangian tex2html_wrap_inline55 . This is now an equivalent 1-body problem for the relative motion, with 3 degrees of freedom tex2html_wrap_inline57 .

Here we start exploiting our knowledge of conservation laws. L is rotationally-invariant, since it depends only on the magnitudes of vectors, which do not change under rotation. Thus the corresponding Noether charge, angular momentum, is conserved. Since angular momentum is a vector, that actually tells us a lot:

1) The direction of tex2html_wrap_inline59 is conserved. tex2html_wrap_inline61 is perpendicular to the plane determined by tex2html_wrap_inline63 and tex2html_wrap_inline65 ; thus tex2html_wrap_inline67 and tex2html_wrap_inline69 must remain in that same plane forever to preserve the direction of tex2html_wrap_inline71 . This means that our 3-d motion is really only motion in a plane, the plane perpendicular to tex2html_wrap_inline73 .

2) The magnitude l of tex2html_wrap_inline77 is conserved. This becomes clearer when we pick coordinates for our motion in the plane perpendicular to tex2html_wrap_inline79 . For polar coordinates, tex2html_wrap_inline81 . tex2html_wrap_inline83 is cyclic -- the Lagrangian does not explicitly depend on tex2html_wrap_inline85 -- so that the momentum conjugate to tex2html_wrap_inline87 is conserved. This conjugate momentum is tex2html_wrap_inline89 -- precisely equal to l, the magnitude of the angular momentum. Thus the tex2html_wrap_inline93 E-L equation is solved by forcing tex2html_wrap_inline95 to remain constant.

This conservation of l by the motion in tex2html_wrap_inline99 has a geometric interpretation known as Kepler's second law. As the system tex2html_wrap_inline101 evolves, its radial vector sweeps out a wedge in the plane. The rate at which the area of that wedge increases is constant: dA for a little piece of wedge is just tex2html_wrap_inline105 (that is, 1/2 base times height), so that tex2html_wrap_inline109 , proportional to l. l conservation means that this rate is constant. Kepler derived this law for the elliptical orbits caused by gravity; here we see that it is a very general consequence of gravity being a central force.

So angular momentum conservation reduces us to only one variable, r. Substituting tex2html_wrap_inline117 into the E-L equations for r gives us an E-L for r that depends only on r and tex2html_wrap_inline125 . This E-L has an effective force driving tex2html_wrap_inline127 of tex2html_wrap_inline129 , equivalent to the force produced by the effective potential tex2html_wrap_inline131 . Thus we have reduced the problem to a 1-dimensional problem for r, with tex2html_wrap_inline135 . This L has no explicit time-dependence, so the energy tex2html_wrap_inline139 is conserved. We thus have a problem of 1-d motion in a potential, where the original potential picks up an extra piece tex2html_wrap_inline141 , which acts as a "centrifugal barrier" to bringing the particles together by reducing r. (This makes sense because tex2html_wrap_inline145 must spin faster to carry the same angular momentum as r is decreased -- which costs more and more rotational energy, until the system's entire energy is rotational and r can decrease no further.)

--

KB




next up previous
Next: About this document

Katherine Benson
Mon Nov 20 14:08:41 EST 1995