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After drawing several periodic near-circular orbits, we went on to consider the more general solution of the central force motion problem: to find all orbits, with no approximations. We found we could use our old one-dimensional tricks, and get an integral equation relating the duration of the motion to an integral over r, giving us the function t(r). This we could invert to get r(t). We could then integrate tex2html_wrap_inline19 to get tex2html_wrap_inline21 , by substituting our solution r(t) into tex2html_wrap_inline25 . Alternatively, if we were only interested in the orbit's shape tex2html_wrap_inline27 , we found an integral equation relating the change in polar angle during the motion to an integral over r, giving tex2html_wrap_inline31 , which we could invert to give the shape tex2html_wrap_inline33 .

The above is an entirely deterministic algorithm to find the orbits for a general central force. It could be fed into a computer program, since integrating is trivial on a computer (just add all the area slices under the curve). However, this procedure is often hard for us humans to do analytically.

Instead, we return to the E-L equation for r(t). If we're only interested in the shape tex2html_wrap_inline37 of the orbit, we can convert our t-derivatives to tex2html_wrap_inline41 -derivatives using the chain rule: tex2html_wrap_inline43 . We know tex2html_wrap_inline45 , so we have tex2html_wrap_inline47 . Substituting this expression in everywhere we see a d/dt gives a new differential equation, which simplifies with the substitution tex2html_wrap_inline51 . This substitution gives us the orbit equation for tex2html_wrap_inline53 .

We pointed out the following qualitative feature of the orbit equation. At a turning point P, where tex2html_wrap_inline57 (and tex2html_wrap_inline59 by choice of starting point), we have a reflection symmetry of the orbit equation. That is, if tex2html_wrap_inline61 obeys the orbit equation, tex2html_wrap_inline63 must also obey it, as neither the equation nor the initial condition changes form under the reflection. Thus if we've solved for the orbit PQ between turning points P and Q, we can extend the orbit indefinitely through time by iteratively reflecting the previous piece of orbit about the current turning point.

We stated Bertrand's theorem about whether such a procedure gives a closed (periodic) orbit, i.e. about whether such a trajectory ever returns to its beginning point. Only for two possible force laws -- inverse square and simple harmonic -- are all bound orbits periodic.

We then specialized to the case of planetary motion, using the orbit equation for tex2html_wrap_inline71 for an attractive inverse square law force. The orbit equation then looks like the differential equation for a simple harmonic oscillator with a constant driving force. We solved this, getting tex2html_wrap_inline73 .

We related the parameter e (called the "eccentricity") to the orbit's energy. Discussed expectations for the solutions' behavior for different energies, based on the effective potential for r. We expect bound orbits for tex2html_wrap_inline79 , barely free orbits (where the velocity decays to zero as r goes to infinity) for E= 0, and scattering orbits for tex2html_wrap_inline85 .

--

KB




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Katherine Benson
Wed Nov 27 17:09:37 EST 1996