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We studied how our energetic predictions for the orbits due to a gravitational central force manifest themselves in the geometry of our solutions tex2html_wrap_inline33 . For tex2html_wrap_inline35 ( tex2html_wrap_inline37 ), we verified that our solution has both minima and maxima for r, so we get a bound orbit tex2html_wrap_inline41 . This orbit will turn out to be an ellipse with the origin at one focus. For E=0 and tex2html_wrap_inline45 (e=1 and tex2html_wrap_inline49 respectively), we verified that the maximum tex2html_wrap_inline51 goes to infinity, so we get a scattering orbit where r can escape to infinity. These orbits will turn out to be left-opening parabolas and hyperbolas respectively, each with the origin at one focus.

Then looked at the orbits in more detail. For tex2html_wrap_inline55 , we calculated (from our solution) tex2html_wrap_inline57 , tex2html_wrap_inline59 , and tex2html_wrap_inline61 . We found the orbit had both its closest and furthest points of approach on the x-axis, consistent with an elliptical shape. Assuming that the shape is elliptical, our values for tex2html_wrap_inline65 , tex2html_wrap_inline67 and tex2html_wrap_inline69 determine all the parameters of the ellipse, as we calculated. It is then a matter of algebra to show that our solution obeys the defining equation of an ellipse with those parameters (that is, that each point on the ellipse has the same total distance 2a from the two foci).

We then discussed the scattering solutions. We found that they have a closest approach at tex2html_wrap_inline73 , where tex2html_wrap_inline75 is positive. r becomes infinite at tex2html_wrap_inline79 , tex2html_wrap_inline81 . Thus (for tex2html_wrap_inline83 increasing in time), our interaction proceeds as follows: the planet comes in from infinite r at angle tex2html_wrap_inline87 (in the third, or lower left, quadrant), comes in to a closest approach at tex2html_wrap_inline89 with positive x, and departs out to infinite r at angle tex2html_wrap_inline95 (in the second, or upper left, quadrant). For e=0, tex2html_wrap_inline99 , so the orbit is asymptotically horizontal; otherwise it opens up at fixed angle.

We calculated tex2html_wrap_inline101 at tex2html_wrap_inline103 . From this it is again only algebraic to show that, for e=1, our solution obeys a parabolic equation, with a focus at the origin and directrix given by the line x= 1/C. For tex2html_wrap_inline109 , more algebra shows that our orbit is the left branch of a hyperbola, whose parameters we displayed. We discussed the asymptotes to the hyperbola, which approximate our orbit as r starts out from or returns to infinity.

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KB




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Katherine Benson
Wed Nov 27 17:14:47 EST 1996