Lecture 3 Last time we saw that we could write Newton II in a coordinate-independent way, the Euler-Lagrange equations, but that these equations involved an ad hoc definition of the partial derivative of the Lagrangian. Today we show that the E-L equations can be derived in a sensible and rigorous way from a simple physical principle, called Hamilton's principle. Hamilton's principle states that of all possible particle motions between an initial point q_i, t_i and final point q_f, t_f, a classical particle follows the specific path such that the action S --- defined as the time integral of the Lagrangian over the motion --- is extremal (i.e., either a maximum or minimum). We discussed why a path has extremal action if and only if the first order variation of the action around it vanishes --- otherwise, nearby paths would exist with both higher and lower values of the action. We then calculated the first order variation of the action, using the chain rule to relate the total change in the Lagrangian to the changes in each of its arguments. We then used the fact that fluctuations in \dot{q_i} are related to those in q_i; specifically, \delta \dot{q_i} = d/dt (\delta q_i). This allowed us to integrate the \delta \dot{q_i} contribution by parts to get independent contributions to \delta S due to variations in each coordinate \delta q_i. For an extremal path, the first order variation \delta S must vanish for *all* variations in the path \delta q_i; this can be true only if the coefficient to \delta q_i in the integrand vanishes. Imposing this condition gives the Euler-Lagrange equations. We began a discussion of a feature of the Lagrangian form of mechanics which makes it such a useful prototype for field theory: that it makes the role of symmetries and conservation laws particularly clear. Because Hamilton's principle is so simple, it is simple to see when a transformation is a symmetry --- that is, when it doesn't change the path that extremizes the action. We first noted that the Lagrangian is not unique: shifting the Lagrangian by a total time derivative, L' = L + d/dt (F(q_k, t) ) doesn't change the extremal paths. This is because the shifted Lagrangian gives an action S' = S + F(q_f, t_f) - F(q_i, t_i), doing the time integral of L'. When we restrict ourselves to considering motions between a fixed pair of endpoints q_i and q_f, this shift between S and S' is the same for each path. Thus only the overall scale for the action looks different in the two pictures: the relative ranking of which paths have the least and most action remains the same. Both Lagrangians produce the same classical motions --- the extremal paths -- and so have the same E-L equations (which are true for the extremal paths). They are equivalent descriptions of the same physical system. We now look for symmetries and conservation laws. Being precise, we call a quantity Q conserved if \dot{Q} = 0. We note that some conservation laws drop right out from the form of the E-L equations. If \partial L/\partial q_i = 0 (that is, L has no explicit dependence on q_i), then E-L tells us that \partial L/\partial (\dot{q_i}) is conserved. We call such a coordinate "cyclic", and the quantity \partial L/\partial (\dot{q_i}) its "conjugate momentum". Showed that for polar coords and a rotationally symmetric potential, \theta is a cyclic coordinate and its conjugate momentum, angular momentum, is conserved. Then claimed that such conservation laws are associated with symmetries: coordinate transformations that leave the system's E-L equations unchanged. Conservation laws for cyclic coordinates stem from invariance of the Lagrangian under the transformation q --> q + \epsilon. (for polar coords, invariance under the rotation \theta --> \theta + \epsilon). Discussed example of transformations that might be symmetries for some physical systems: space translations; time translations (which translate the coordinates indirectly through the chain rule); and space rotations about an axis. Next time we'll see that for every such symmetry, we can construct a conserved charge Q. --- KB